k^2=0.49k

Solution for k^2=0.49k equation:

k^2=0.49k

We move all terms to the left:

k^2-(0.49k)=0

We add all the numbers together, and all the variables

k^2-(+0.49k)=0

We get rid of parentheses

k^2-0.49k=0

a = 1; b = -0.49; c = 0;
Δ = b2-4ac
Δ = -0.492-4·1·0
Δ = 0.2401
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$k_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$k_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$k_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-0.49)-\sqrt{0.2401}}{2*1}=\frac{0.49-\sqrt{0.2401}}{2}
$
$k_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-0.49)+\sqrt{0.2401}}{2*1}=\frac{0.49+\sqrt{0.2401}}{2}
$